8v^2+80v+128=0

Solution for 8v^2+80v+128=0 equation:

8v^2+80v+128=0

a = 8; b = 80; c = +128;
Δ = b2-4ac
Δ = 802-4·8·128
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-48}{2*8}=\frac{-128}{16}
=-8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+48}{2*8}=\frac{-32}{16}
=-2
$